AAO Exam-CT 11: Reasoning (Puzzle - Scheduling)
AAO Exam-CT 11- Reasoning (Puzzle - Scheduling)
1. Directions: Read the following information carefully and answer the questions given below.
Eight persons – R, S, T, U, W, X, Y and Z – gave the exam in four different months among – April, May, June and July – on different dates among – 7th and 28th – of the same year. No two persons gave on the same date of the same month.
Only two persons gave after U. Only one person gave between U and S. S and R gave exams on different dates. R gave an exam after S. Five persons gave exam between W and T. T gave before R and both gave on different dates. Y gave after Z, who gave in the month which has odd number of days. Y and W did not give in the same month.
-
April
-
May
-
July
-
Cannot be determined
Persons – 8; R, S, T, U, W, X, Y and Z;
Months – April, May, June and July;
Dates – 7th and 28th;
1. Only two persons gave after U.
2. Only one person gave between U and S.
From this we get the possible arrangements:
|
Months (Days) |
Date |
Case I |
Case II |
|
April (30) |
7th |
|
|
|
28th |
|
|
|
|
May (31) |
7th |
|
|
|
28th |
S |
|
|
|
June (30) |
7th |
|
|
|
28th |
U |
U |
|
|
July (31) |
7th |
|
|
|
28th |
|
S |
3. S and R gave on different dates.
4. R gave after S.
From this case II is eliminated as we cannot determine the month in which R gave the exam.
|
Months (Days) |
Date |
Case I |
Case I (a) |
|
April (30) |
7th |
|
|
|
28th |
|
|
|
|
May (31) |
7th |
|
|
|
28th |
S |
S |
|
|
June (30) |
7th |
R |
|
|
28th |
U |
U |
|
|
July (31) |
7th |
|
R |
|
28th |
|
|
5. Five persons gave between W and T.
6. T gave before R and both gave on different dates.
|
Months (Days) |
Date |
Case I |
Case I (a) |
|
April (30) |
7th |
|
|
|
28th |
T |
T |
|
|
May (31) |
7th |
|
|
|
28th |
S |
S |
|
|
June (30) |
7th |
R |
|
|
28th |
U |
U |
|
|
July (31) |
7th |
|
R |
|
28th |
W |
W |
7. Y gave after Z, who gave in the month which has odd number of days.
|
Months (Days) |
Date |
Case I |
Case I (a) |
|
April (30) |
7th |
X |
X |
|
28th |
T |
T |
|
|
May (31) |
7th |
Z |
Z |
|
28th |
S |
S |
|
|
June (30) |
7th |
R |
Y |
|
28th |
U |
U |
|
|
July (31) |
7th |
Y |
R |
|
28th |
W |
W |
8. Y and W did not give in the same month.
From this case I is eliminated, as Y and W attended in the same month which is not possible. From this we get the final arrangement as follows.
|
Months (Days) |
Date |
Case I (a) |
|
April (30) |
7th |
X |
|
28th |
T |
|
|
May (31) |
7th |
Z |
|
28th |
S |
|
|
June (30) |
7th |
Y |
|
28th |
U |
|
|
July (31) |
7th |
R |
|
28th |
W |
Hence, Y gave the exam in the month of June.
2. Directions: Read the following information carefully and answer the questions given below.
Eight persons – R, S, T, U, W, X, Y and Z – gave the exam in four different months among – April, May, June and July – on different dates among – 7th and 28th – of the same year. No two persons gave on the same date of the same month.
Only two persons gave after U. Only one person gave between U and S. S and R gave exams on different dates. R gave an exam after S. Five persons gave exam between W and T. T gave before R and both gave on different dates. Y gave after Z, who gave in the month which has odd number of days. Y and W did not give in the same month.
-
Two
-
Three
-
Four
-
More than four
Persons – 8; R, S, T, U, W, X, Y and Z;
Months – April, May, June and July;
Dates – 7th and 28th;
1. Only two persons gave after U.
2. Only one person gave between U and S.
From this we get the possible arrangements:
|
Months (Days) |
Date |
Case I |
Case II |
|
April (30) |
7th |
|
|
|
28th |
|
|
|
|
May (31) |
7th |
|
|
|
28th |
S |
|
|
|
June (30) |
7th |
|
|
|
28th |
U |
U |
|
|
July (31) |
7th |
|
|
|
28th |
|
S |
3. S and R gave on different dates.
4. R gave after S.
From this case II is eliminated as we cannot determine the month in which R gave the exam.
|
Months (Days) |
Date |
Case I |
Case I (a) |
|
April (30) |
7th |
|
|
|
28th |
|
|
|
|
May (31) |
7th |
|
|
|
28th |
S |
S |
|
|
June (30) |
7th |
R |
|
|
28th |
U |
U |
|
|
July (31) |
7th |
|
R |
|
28th |
|
|
5. Five persons gave between W and T.
6. T gave before R and both gave on different dates.
|
Months (Days) |
Date |
Case I |
Case I (a) |
|
April (30) |
7th |
|
|
|
28th |
T |
T |
|
|
May (31) |
7th |
|
|
|
28th |
S |
S |
|
|
June (30) |
7th |
R |
|
|
28th |
U |
U |
|
|
July (31) |
7th |
|
R |
|
28th |
W |
W |
7. Y gave after Z, who gave in the month which has odd number of days.
|
Months (Days) |
Date |
Case I |
Case I (a) |
|
April (30) |
7th |
X |
X |
|
28th |
T |
T |
|
|
May (31) |
7th |
Z |
Z |
|
28th |
S |
S |
|
|
June (30) |
7th |
R |
Y |
|
28th |
U |
U |
|
|
July (31) |
7th |
Y |
R |
|
28th |
W |
W |
8. Y and W did not give in the same month.
From this case I is eliminated, as Y and W attended in the same month which is not possible. From this we get the final arrangement as follows.
|
Months (Days) |
Date |
Case I (a) |
|
April (30) |
7th |
X |
|
28th |
T |
|
|
May (31) |
7th |
Z |
|
28th |
S |
|
|
June (30) |
7th |
Y |
|
28th |
U |
|
|
July (31) |
7th |
R |
|
28th |
W |
Hence, only one person gave the exam between X and Z.
3. Directions: Read the following information carefully and answer the questions given below.
Eight persons – R, S, T, U, W, X, Y and Z – gave the exam in four different months among – April, May, June and July – on different dates among – 7th and 28th – of the same year. No two persons gave on the same date of the same month.
Only two persons gave after U. Only one person gave between U and S. S and R gave exams on different dates. R gave an exam after S. Five persons gave exam between W and T. T gave before R and both gave on different dates. Y gave after Z, who gave in the month which has odd number of days. Y and W did not give in the same month.
-
Z
-
R
-
Y
-
X
Persons – 8; R, S, T, U, W, X, Y and Z;
Months – April, May, June and July;
Dates – 7th and 28th;
1. Only two persons gave after U.
2. Only one person gave between U and S.
From this we get the possible arrangements:
|
Months (Days) |
Date |
Case I |
Case II |
|
April (30) |
7th |
|
|
|
28th |
|
|
|
|
May (31) |
7th |
|
|
|
28th |
S |
|
|
|
June (30) |
7th |
|
|
|
28th |
U |
U |
|
|
July (31) |
7th |
|
|
|
28th |
|
S |
3. S and R gave on different dates.
4. R gave after S.
From this case II is eliminated as we cannot determine the month in which R gave the exam.
|
Months (Days) |
Date |
Case I |
Case I (a) |
|
April (30) |
7th |
|
|
|
28th |
|
|
|
|
May (31) |
7th |
|
|
|
28th |
S |
S |
|
|
June (30) |
7th |
R |
|
|
28th |
U |
U |
|
|
July (31) |
7th |
|
R |
|
28th |
|
|
5. Five persons gave between W and T.
6. T gave before R and both gave on different dates.
|
Months (Days) |
Date |
Case I |
Case I (a) |
|
April (30) |
7th |
|
|
|
28th |
T |
T |
|
|
May (31) |
7th |
|
|
|
28th |
S |
S |
|
|
June (30) |
7th |
R |
|
|
28th |
U |
U |
|
|
July (31) |
7th |
|
R |
|
28th |
W |
W |
7. Y gave after Z, who gave in the month which has odd number of days.
|
Months (Days) |
Date |
Case I |
Case I (a) |
|
April (30) |
7th |
X |
X |
|
28th |
T |
T |
|
|
May (31) |
7th |
Z |
Z |
|
28th |
S |
S |
|
|
June (30) |
7th |
R |
Y |
|
28th |
U |
U |
|
|
July (31) |
7th |
Y |
R |
|
28th |
W |
W |
8. Y and W did not give in the same month.
From this case I is eliminated, as Y and W attended in the same month which is not possible. From this we get the final arrangement as follows.
|
Months (Days) |
Date |
Case I (a) |
|
April (30) |
7th |
X |
|
28th |
T |
|
|
May (31) |
7th |
Z |
|
28th |
S |
|
|
June (30) |
7th |
Y |
|
28th |
U |
|
|
July (31) |
7th |
R |
|
28th |
W |
Except W, all other persons gave the exam in odd numbered date.
Hence, W is the odd one out.
4. Directions: Read the following information carefully and answer the questions given below.
Eight persons – R, S, T, U, W, X, Y and Z – gave the exam in four different months among – April, May, June and July – on different dates among – 7th and 28th – of the same year. No two persons gave on the same date of the same month.
Only two persons gave after U. Only one person gave between U and S. S and R gave exams on different dates. R gave an exam after S. Five persons gave exam between W and T. T gave before R and both gave on different dates. Y gave after Z, who gave in the month which has odd number of days. Y and W did not give in the same month.
-
W
-
U
-
S
-
Z
Persons – 8; R, S, T, U, W, X, Y and Z;
Months – April, May, June and July;
Dates – 7th and 28th;
1. Only two persons gave after U.
2. Only one person gave between U and S.
From this we get the possible arrangements:
|
Months (Days) |
Date |
Case I |
Case II |
|
April (30) |
7th |
|
|
|
28th |
|
|
|
|
May (31) |
7th |
|
|
|
28th |
S |
|
|
|
June (30) |
7th |
|
|
|
28th |
U |
U |
|
|
July (31) |
7th |
|
|
|
28th |
|
S |
3. S and R gave on different dates.
4. R gave after S.
From this case II is eliminated as we cannot determine the month in which R gave the exam.
|
Months (Days) |
Date |
Case I |
Case I (a) |
|
April (30) |
7th |
|
|
|
28th |
|
|
|
|
May (31) |
7th |
|
|
|
28th |
S |
S |
|
|
June (30) |
7th |
R |
|
|
28th |
U |
U |
|
|
July (31) |
7th |
|
R |
|
28th |
|
|
5. Five persons gave between W and T.
6. T gave before R and both gave on different dates.
|
Months (Days) |
Date |
Case I |
Case I (a) |
|
April (30) |
7th |
|
|
|
28th |
T |
T |
|
|
May (31) |
7th |
|
|
|
28th |
S |
S |
|
|
June (30) |
7th |
R |
|
|
28th |
U |
U |
|
|
July (31) |
7th |
|
R |
|
28th |
W |
W |
7. Y gave after Z, who gave in the month which has odd number of days.
|
Months (Days) |
Date |
Case I |
Case I (a) |
|
April (30) |
7th |
X |
X |
|
28th |
T |
T |
|
|
May (31) |
7th |
Z |
Z |
|
28th |
S |
S |
|
|
June (30) |
7th |
R |
Y |
|
28th |
U |
U |
|
|
July (31) |
7th |
Y |
R |
|
28th |
W |
W |
8. Y and W did not give in the same month.
From this case I is eliminated, as Y and W attended in the same month which is not possible. From this we get the final arrangement as follows.
|
Months (Days) |
Date |
Case I (a) |
|
April (30) |
7th |
X |
|
28th |
T |
|
|
May (31) |
7th |
Z |
|
28th |
S |
|
|
June (30) |
7th |
Y |
|
28th |
U |
|
|
July (31) |
7th |
R |
|
28th |
W |
Here, the number of persons who gave the exam before R is six similarly the number of persons gave the exam after T is also six.
Hence, T is the correct answer.
5. Directions: Read the following information carefully and answer the questions given below.
Eight persons – R, S, T, U, W, X, Y and Z – gave the exam in four different months among – April, May, June and July – on different dates among – 7th and 28th – of the same year. No two persons gave on the same date of the same month.
Only two persons gave after U. Only one person gave between U and S. S and R gave exams on different dates. R gave an exam after S. Five persons gave exam between W and T. T gave before R and both gave on different dates. Y gave after Z, who gave in the month which has odd number of days. Y and W did not give in the same month.
-
28th May
-
28th April
-
7th July
-
7th May
Persons – 8; R, S, T, U, W, X, Y and Z;
Months – April, May, June and July;
Dates – 7th and 28th;
1. Only two persons gave after U.
2. Only one person gave between U and S.
From this we get the possible arrangements:
|
Months (Days) |
Date |
Case I |
Case II |
|
April (30) |
7th |
|
|
|
28th |
|
|
|
|
May (31) |
7th |
|
|
|
28th |
S |
|
|
|
June (30) |
7th |
|
|
|
28th |
U |
U |
|
|
July (31) |
7th |
|
|
|
28th |
|
S |
3. S and R gave on different dates.
4. R gave after S.
From this case II is eliminated as we cannot determine the month in which R gave the exam.
|
Months (Days) |
Date |
Case I |
Case I (a) |
|
April (30) |
7th |
|
|
|
28th |
|
|
|
|
May (31) |
7th |
|
|
|
28th |
S |
S |
|
|
June (30) |
7th |
R |
|
|
28th |
U |
U |
|
|
July (31) |
7th |
|
R |
|
28th |
|
|
5. Five persons gave between W and T.
6. T gave before R and both gave on different dates.
|
Months (Days) |
Date |
Case I |
Case I (a) |
|
April (30) |
7th |
|
|
|
28th |
T |
T |
|
|
May (31) |
7th |
|
|
|
28th |
S |
S |
|
|
June (30) |
7th |
R |
|
|
28th |
U |
U |
|
|
July (31) |
7th |
|
R |
|
28th |
W |
W |
7. Y gave after Z, who gave in the month which has odd number of days.
|
Months (Days) |
Date |
Case I |
Case I (a) |
|
April (30) |
7th |
X |
X |
|
28th |
T |
T |
|
|
May (31) |
7th |
Z |
Z |
|
28th |
S |
S |
|
|
June (30) |
7th |
R |
Y |
|
28th |
U |
U |
|
|
July (31) |
7th |
Y |
R |
|
28th |
W |
W |
8. Y and W did not give in the same month.
From this case I is eliminated, as Y and W attended in the same month which is not possible. From this we get the final arrangement as follows.
|
Months (Days) |
Date |
Case I (a) |
|
April (30) |
7th |
X |
|
28th |
T |
|
|
May (31) |
7th |
Z |
|
28th |
S |
|
|
June (30) |
7th |
Y |
|
28th |
U |
|
|
July (31) |
7th |
R |
|
28th |
W |
Hence, X gave the exam on 7th in April.
Eight Persons P, Q, R, S, T, U, V and W were born in eight different years i.e., 1980, 1984, 1989, 1991, 1993, 1995, 1996 and 2000 but not necessarily in the same order. All calculations are done with respect to the year, 2022 assuming the month and date to be the same as that of the years mentioned above.
The age of R is an odd perfect cube number. Difference between the ages of R and W is 5 years. U is older than S. Difference between the ages of S and U is a perfect square number. The age of S is above 30 years. P is younger than Q. T is 2 years older than Q. More than three persons were born between P and V.
How many persons are born between P and S?
-
Two
-
Four
-
Six
-
None of these
From the given statements,
1) The age of R is an odd perfect cube number. As R's age is 27 which is perfect cube of 3.
|
Year |
Age |
Person |
|
1980 |
42 |
|
|
1984 |
38 |
|
|
1989 |
33 |
|
|
1991 |
31 |
|
|
1993 |
29 |
|
|
1995 |
27 |
R |
|
1996 |
26 |
|
|
2000 |
22 |
|
2) Difference between the ages of R and W is 5 years. As W's age is 22 hence a difference between the age of R and W = 27- 22 = 5 years.
|
Year |
Age |
Person |
|
1980 |
42 |
|
|
1984 |
38 |
|
|
1989 |
33 |
|
|
1991 |
31 |
|
|
1993 |
29 |
|
|
1995 |
27 |
R |
|
1996 |
26 |
|
|
2000 |
22 |
W |
3) In case-1, As age of S is 33 years born in 1989 and age of U is 42 who born on 1980, hence the difference between the age of S and U is 9 which is a perfect square number. The age of S is above 30 years. In case-2, and the age of S is 38 years who was born in 1984, and age of U is 42 years when born in 1980, hence the difference between the age of S and U is 4 which is a perfect square number. U is older than S. Here we get 2 possible cases i.e. Case 1 and Case 2.
|
Year |
Age |
Case-1/Person |
Case-2/ Person |
|
1980 |
42 |
U |
U |
|
1984 |
38 |
|
S |
|
1989 |
33 |
S |
|
|
1991 |
31 |
|
|
|
1993 |
29 |
|
|
|
1995 |
27 |
R |
R |
|
1996 |
26 |
|
|
|
2000 |
22 |
W |
W |
4) T was 2 years older than Q. Hence in case-1, T was born on 1991 and Q was born on 1993 and in case-2, T was born on 1989 and Q was born on 1991.
|
Year |
Age |
Case 1/Person |
Case-2/ Person |
|
1980 |
42 |
U |
U |
|
1984 |
38 |
|
S |
|
1989 |
33 |
S |
T |
|
1991 |
31 |
T |
Q |
|
1993 |
29 |
Q |
|
|
1995 |
27 |
R |
R |
|
1996 |
26 |
|
|
|
2000 |
22 |
W |
W |
5) More than three persons were born between P and V, from this condition Case 2 is ruled out now because there is no place for P and V in case 2 according to the given information. Hence in case 1, P was born in 1996 and V was born in 1984, because P is younger than Q. So, the final arrangement will be-
|
Year |
Age |
Person |
|
1980 |
42 |
U |
|
1984 |
38 |
V |
|
1989 |
33 |
S |
|
1991 |
31 |
T |
|
1993 |
29 |
Q |
|
1995 |
27 |
R |
|
1996 |
26 |
P |
|
2000 |
22 |
W |
Hence, three persons are born between P and S.
Eight Persons P, Q, R, S, T, U, V and W were born in eight different years i.e., 1980, 1984, 1989, 1991, 1993, 1995, 1996 and 2000 but not necessarily in the same order. All calculations are done with respect to the year, 2022 assuming the month and date to be the same as that of the years mentioned above.
The age of R is an odd perfect cube number. Difference between the ages of R and W is 5 years. U is older than S. Difference between the ages of S and U is a perfect square number. The age of S is above 30 years. P is younger than Q. T is 2 years older than Q. More than three persons were born between P and V.
What is the age difference between T and R?
-
2
-
5
-
8
-
None of these
From the given statements,
1) The age of R is an odd perfect cube number. As R's age is 27 which is a perfect cube of 3.
|
Year |
Age |
Person |
|
1980 |
42 |
|
|
1984 |
38 |
|
|
1989 |
33 |
|
|
1991 |
31 |
|
|
1993 |
29 |
|
|
1995 |
27 |
R |
|
1996 |
26 |
|
|
2000 |
22 |
|
2) Difference between the ages of R and W is 5 years. As W's age is 22 hence difference between the age of R and W = 27- 22 = 5 years.
|
Year |
Age |
Person |
|
1980 |
42 |
|
|
1984 |
38 |
|
|
1989 |
33 |
|
|
1991 |
31 |
|
|
1993 |
29 |
|
|
1995 |
27 |
R |
|
1996 |
26 |
|
|
2000 |
22 |
W |
3) In case 1, As age of S is 33 years who born n 1989 and age of U is 42 who born in 1980, hence the difference between the age of S and U is 9 which is a perfect square number. The age of S is above 30 years. In case-2, and the age of S is 38 years who was born in 1984 and age of U is 42 years who born in 1980, hence the difference between the age of S and U is 4 which is a perfect square number. U is older than S. Here we get 2 possible cases i.e. Case 1 and Case 2.
|
Year |
Age |
Case-1/Person |
Case-2/ Person |
|
1980 |
42 |
U |
U |
|
1984 |
38 |
|
S |
|
1989 |
33 |
S |
|
|
1991 |
31 |
|
|
|
1993 |
29 |
|
|
|
1995 |
27 |
R |
R |
|
1996 |
26 |
|
|
|
2000 |
22 |
W |
W |
4) T was 2 years older than Q. Hence, in case-1, T was born in 1991, Q was born in 1993 and in case-2, T was born in 1989 and Q was born in 1991.
|
Year |
Age |
Case-1/Person |
Case-2/ Person |
|
1980 |
42 |
U |
U |
|
1984 |
38 |
|
S |
|
1989 |
33 |
S |
T |
|
1991 |
31 |
T |
Q |
|
1993 |
29 |
Q |
|
|
1995 |
27 |
R |
R |
|
1996 |
26 |
|
|
|
2000 |
22 |
W |
W |
5) More than three persons were born between P and V, from this condition Case 2 is ruled out now because there is no place for P and V in case 2 according to the given information. Hence in case 1, P was born in 1996 and V was born in 1984, because P is younger than Q. So, the final arrangement will be-
|
Year |
Age |
Person |
|
1980 |
42 |
U |
|
1984 |
38 |
V |
|
1989 |
33 |
S |
|
1991 |
31 |
T |
|
1993 |
29 |
Q |
|
1995 |
27 |
R |
|
1996 |
26 |
P |
|
2000 |
22 |
W |
Hence, age difference between T and R is 4 years.
Eight Persons P, Q, R, S, T, U, V and W were born in eight different years i.e., 1980, 1984, 1989, 1991, 1993, 1995, 1996 and 2000 but not necessarily in the same order. All calculations are done with respect to the year, 2022 assuming the month and date to be the same as that of the years mentioned above.
The age of R is an odd perfect cube number. Difference between the ages of R and W is 5 years. U is older than S. Difference between the ages of S and U is a perfect square number. The age of S is above 30 years. P is younger than Q. T is 2 years older than Q. More than three persons were born between P and V.
Who born just before V?
-
S
-
T
-
R
-
None of these
From the given statements,
1) The age of R is an odd perfect cube number. As R's age is 27 which is perfect cube of 3.
|
Year |
Age |
Person |
|
1980 |
42 |
|
|
1984 |
38 |
|
|
1989 |
33 |
|
|
1991 |
31 |
|
|
1993 |
29 |
|
|
1995 |
27 |
R |
|
1996 |
26 |
|
|
2000 |
22 |
|
2) Difference between the ages of R and W is 5 years. As W's age is 22 hence difference between the age of R and W = 27- 22 = 5 years.
|
Year |
Age |
Person |
|
1980 |
42 |
|
|
1984 |
38 |
|
|
1989 |
33 |
|
|
1991 |
31 |
|
|
1993 |
29 |
|
|
1995 |
27 |
R |
|
1996 |
26 |
|
|
2000 |
22 |
W |
3) In case-1, As the age of S is 33 years who born on 1989 and the age of U is 42 who born on 1980, hence the difference between the age of S and U is 9 which is a perfect square number. The age of S is above 30 years. In case 2, and the age of S is 38 years who born in 1984 and age of U is 42 years who born in 1980, hence the difference between the age of S and U is 4 which is a perfect square number. U is older than S. Here we get 2 possible cases i.e. Case 1 and Case 2.
|
Year |
Age |
Case-1/Person |
Case-2/ Person |
|
1980 |
42 |
U |
U |
|
1984 |
38 |
|
S |
|
1989 |
33 |
S |
|
|
1991 |
31 |
|
|
|
1993 |
29 |
|
|
|
1995 |
27 |
R |
R |
|
1996 |
26 |
|
|
|
2000 |
22 |
W |
W |
4) T was 2 years older than Q. Hence in case-1, T was born on 1991 and Q was born on 1993 and in case-2, T was born on 1989 and Q was born in 1991.
|
Year |
Age |
Case-1/Person |
Case-2/ Person |
|
1980 |
42 |
U |
U |
|
1984 |
38 |
|
S |
|
1989 |
33 |
S |
T |
|
1991 |
31 |
T |
Q |
|
1993 |
29 |
Q |
|
|
1995 |
27 |
R |
R |
|
1996 |
26 |
|
|
|
2000 |
22 |
W |
W |
5) More than three persons were born between P and V, from this condition Case 2 is ruled out now because there is no place for P and V in case 2 according to the give information. Hence in case 1, P was born on 1996 and V was born in 1984, because P is younger than Q. So, the final arrangement will be-
|
Year |
Age |
Person |
|
1980 |
42 |
U |
|
1984 |
38 |
V |
|
1989 |
33 |
S |
|
1991 |
31 |
T |
|
1993 |
29 |
Q |
|
1995 |
27 |
R |
|
1996 |
26 |
P |
|
2000 |
22 |
W |
Hence, U was born just before V.
Eight Persons P, Q, R, S, T, U, V and W were born in eight different years i.e., 1980, 1984, 1989, 1991, 1993, 1995, 1996 and 2000 but not necessarily in the same order. All calculations are done with respect to the year, 2022 assuming the month and date to be the same as that of the years mentioned above.
The age of R is an odd perfect cube number. Difference between the ages of R and W is 5 years. U is older than S. Difference between the ages of S and U is a perfect square number. The age of S is above 30 years. P is younger than Q. T is 2 years older than Q. More than three persons were born between P and V.
What is the sum of the ages of W and U?
-
20
-
62
-
60
-
None of these
From the given statements,
1) The age of R is an odd perfect cube number. As R's age is 27 which is perfect cube of 3.
|
Year |
Age |
Person |
|
1980 |
42 |
|
|
1984 |
38 |
|
|
1989 |
33 |
|
|
1991 |
31 |
|
|
1993 |
29 |
|
|
1995 |
27 |
R |
|
1996 |
26 |
|
|
2000 |
22 |
|
2) Difference between the ages of R and W is 5 years. As W's age is 22 hence difference between the age of R and W = 27- 22 = 5 years.
|
Year |
Age |
Person |
|
1980 |
42 |
|
|
1984 |
38 |
|
|
1989 |
33 |
|
|
1991 |
31 |
|
|
1993 |
29 |
|
|
1995 |
27 |
R |
|
1996 |
26 |
|
|
2000 |
22 |
W |
3) In case-1, As the age of S is 33 years who born in 1989 and age of U is 42 who born on 1980, hence difference between the age of S and U is 9 which is a perfect square number. The age of S is above 30 years. In case-2, and the age of S is 38 years who born on 1984 and age of U is 42 years who born in 1980, hence the difference between the age of S and U is 4 which is a perfect square number. U is older than S. Here we get 2 possible cases i.e. Case 1 and Case 2.
|
Year |
Age |
Case-1/Person |
Case-2/ Person |
|
1980 |
42 |
U |
U |
|
1984 |
38 |
|
S |
|
1989 |
33 |
S |
|
|
1991 |
31 |
|
|
|
1993 |
29 |
|
|
|
1995 |
27 |
R |
R |
|
1996 |
26 |
|
|
|
2000 |
22 |
W |
W |
4) T was 2 years older than Q. Hence in case-1, T was born on 1991 and Q was born on 1993 and in case-2, T was born on 1989 and Q was born on 1991.
|
Year |
Age |
Case-1/Person |
Case-2/ Person |
|
1980 |
42 |
U |
U |
|
1984 |
38 |
|
S |
|
1989 |
33 |
S |
T |
|
1991 |
31 |
T |
Q |
|
1993 |
29 |
Q |
|
|
1995 |
27 |
R |
R |
|
1996 |
26 |
|
|
|
2000 |
22 |
W |
W |
5) More than three persons were born between P and V, from this condition Case 2 is ruled out now because there is no place for P and V in case 2 according to the given information. Hence in case 1, P was born in 1996 and V was born in 1984, because P is younger than Q. So, the final arrangement will be-
|
Year |
Age |
Person |
|
1980 |
42 |
U |
|
1984 |
38 |
V |
|
1989 |
33 |
S |
|
1991 |
31 |
T |
|
1993 |
29 |
Q |
|
1995 |
27 |
R |
|
1996 |
26 |
P |
|
2000 |
22 |
W |
Hence, the sum of the ages of W and U = 22 + 42 = 64
Eight Persons P, Q, R, S, T, U, V and W were born in eight different years i.e., 1980, 1984, 1989, 1991, 1993, 1995, 1996 and 2000 but not necessarily in the same order. All calculations are done with respect to the year, 2022 assuming the month and date to be the same as that of the years mentioned above.
The age of R is an odd perfect cube number. Difference between the ages of R and W is 5 years. U is older than S. Difference between the ages of S and U is a perfect square number. The age of S is above 30 years. P is younger than Q. T is 2 years older than Q. More than three persons were born between P and V.
Four of the following five are alike in a certain way based on their position. Which of the following does not belongs to that group?
-
S
-
T
-
R
-
Q
From the given statements,
1) The age of R is an odd perfect cube number. As R's age is 27 which is perfect cube of 3.
|
Year |
Age |
Person |
|
1980 |
42 |
|
|
1984 |
38 |
|
|
1989 |
33 |
|
|
1991 |
31 |
|
|
1993 |
29 |
|
|
1995 |
27 |
R |
|
1996 |
26 |
|
|
2000 |
22 |
|
2) Difference between the ages of R and W is 5 years. As W's age is 22 hence difference between the age of R and W = 27- 22 = 5 years.
|
Year |
Age |
Person |
|
1980 |
42 |
|
|
1984 |
38 |
|
|
1989 |
33 |
|
|
1991 |
31 |
|
|
1993 |
29 |
|
|
1995 |
27 |
R |
|
1996 |
26 |
|
|
2000 |
22 |
W |
3) In case-1, As age of S is 33 years who born on 1989 and age of U is 42 who born on 1980, hence difference between the age of S and U is 9 which is a perfect square number. The age of S is above 30 years. In case-2, and the age of S is 38 years who born on 1984 and age of U is 42 years who born on 1980, hence difference between the age of S and U is 4 which is a perfect square number. U is older than S. Here we get 2 possible cases i.e. Case 1 and Case 2.
|
Year |
Age |
Case-1/Person |
Case-2/ Person |
|
1980 |
42 |
U |
U |
|
1984 |
38 |
|
S |
|
1989 |
33 |
S |
|
|
1991 |
31 |
|
|
|
1993 |
29 |
|
|
|
1995 |
27 |
R |
R |
|
1996 |
26 |
|
|
|
2000 |
22 |
W |
W |
4) T was 2 years older than Q. Hence in case-1, T was born in 1991 and Q was born in 1993 and in case-2, T was born in 1989 and Q was born in 1991.
|
Year |
Age |
Case-1/Person |
Case-2/ Person |
|
1980 |
42 |
U |
U |
|
1984 |
38 |
|
S |
|
1989 |
33 |
S |
T |
|
1991 |
31 |
T |
Q |
|
1993 |
29 |
Q |
|
|
1995 |
27 |
R |
R |
|
1996 |
26 |
|
|
|
2000 |
22 |
W |
W |
5) More than three persons were born between P and V, from this condition Case-2 is ruled out now because there is no place for P and V in case 2 according to the given information. Hence in case 1 , P was born in 1996 and V was born in 1984, because P is younger than Q. So, the final arrangement will be-
|
Year |
Age |
Person |
|
1980 |
42 |
U |
|
1984 |
38 |
V |
|
1989 |
33 |
S |
|
1991 |
31 |
T |
|
1993 |
29 |
Q |
|
1995 |
27 |
R |
|
1996 |
26 |
P |
|
2000 |
22 |
W |
Hence, Except for U’s age all other persons age is an odd number.
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